Tostr(int n) : useful function to change integer / long long to string !!

string tostr(int n)
{
    stringstream ss;
    ss<<n;
    string s=ss.str();
    return s;
}

Comments

Post a Comment

Popular posts from this blog

Two Pointers Technique & Binary Search For Beginners

Sample Problem: Electronics Shop ( HackerRank ) (Find me on HackerRank @ Handle:  BishalG  ) Problem Summary: In this problem, you are given two arrays of positive integer numbers of lengths n and m respectively and another positive integer b . Your task is to find out the maximum integer formed by the summation of two integer values taken from different arrays and is less than or equal to b. If there does not exist such summation print -1 . Solution Idea: Since the constraints for n and m are small ( i.e. 1 <= n, m <= 1000 ) , so this problem is very much suitable to test different variants of our solution approaches. Here, we will discuss about 3 different approaches to solve this problem progressively starting from least efficient solution to most efficient one. Approach - 1: Brute-force If we think in brute-force manner, the naive approach to solve this problem will be to try every possible pairing among these two arrays. For this, we can just it...
Read more

HackerRank: Find Maximum Index Product ( Stack, DS, Histogram Logic )

HackerRank: Find Maximum Index Product ( Stack, DS ) (Find me on HackerRank @ Handle: BishalG ) Problem Summary: According to problem, you are given an array A of length n . For each index - i in the array, calculate IndexProduct(i) which is defined as: IndexProduct(i) = Left(i) * Right(i).  Again, Left(i) and Right(i) has following definition: Left(i) = Index on the left side of the array such that j < i and arr[j] > arr[i] Right(i) = Index on the right side of the array such that j > i and arr[j] > arr[i] If such index does not exist then it would be 0 in both cases. Our task is to find maximum of IndexProduct(i) among all values of i. Solution Idea: I'm explaining here the idea for generating values for Left array. Similar concept can be applied to find the values for Right array. After finding both arrays, we can easily calculate IndexProduct for every i and find the maximum value among them which will be our answer. Calculating Left array: If we think ...
Read more

Problem : Codeforces Round #406 (Div. 1) B [ Legacy ]( Dijakstra, Segment tree)

You are given graph N (10^5) nodes and starting node (S), You have to find min distance needed to go to all other nodes. Connections among nodes are a little bit different in the form of range type queries, which are: (1) you can open a portal from planet u to planet v with cost z. (2) you can open a portal from planet u to any planet with index in range [l, r] with cost z. (3) you can open a portal from any planet with index in range [l, r] to planet u with cost z. Idea: If we tried to make a adjacency matrix normally by traversing from l to r in (2) and (3) type of connection queries, it will surely time out. So, what we have to do is to think little bit about segmenttree representation of array. This representation allow us to make connection matrix only with LOGN adjacency nodes. So that we may proceed further. Lets build two types of segment-tree nodes , say UP segment tree , which will be used for (2) type of query and DOWN segmenttree which will be used for (3) type of ...
Read more