UVA-12062 - Reverse Assignment


UVA: 12062 - Reverse Assignment


///============================================================================///
/// ///
/// IT'S ME ///
/// BISHAL GAUTAM ///
/// CSE,JAHANGIRNAGAR UNIVERSITY,DHAKA ///
/// "Follow Excellence..Success will chase U" ///
/// ///
///============================================================================///
#include<bits/stdc++.h>
#define PI acos(-1.0)
#define X first
#define Y second
#define mpp make_pair
#define nl printf("\n")
#define SZ(x) (int)(x.size())
#define pb(x) push_back(x)
#define pii pair<int,int>
#define pll pair<ll,ll>
#define pdd pair<double,double>

///==Scanning====///
#define S(a) scanf("%d",&a)
#define P(a) printf("%d",a)
#define SL(a) scanf("%lld",&a)
#define S2(a,b) scanf("%d%d",&a,&b)
#define S3(a,b,c) scanf("%d%d%d",&a,&b,&c)
#define SL2(a,b) scanf("%lld%lld",&a,&b)
#define SL3(a,b,c) scanf("%lld%lld%lld",&a,&b,&c)

///==Arr,Vec Functions==///
#define all(v) v.begin(),v.end()
#define CLR(a) memset(a,0,sizeof(a))
#define SET(a) memset(a,-1,sizeof(a))
#define CPY(a,b) memcpy(a,b,sizeof(a))
#define MAX(a) (*max_element(all(a)))
#define MIN(a) (*min_element(all(a)))
#define fv(i,v) for(int i=0;i<(int)v.size();i++)
#define fr(i,a,n) for(int i=a;i<=n;i++)
#define rf(i,n,a) for(int i=n;i>=a;i--)

///===Some Useful====///
#define OnBit(a) __builtin_popcountll((ll)a)
#define LB(v,k) lower_bound(v.begin(),v.end(),k)
#define _cin ios_base::sync_with_stdio(0),cin.tie(0)
#define dbg(x) cerr<<__LINE__<< ":: "<<#x<<"= "<<x<<endl
#define UNIK(v) sort(all(v)),v.resize( unique(all(v)) -v.begin() );
#define fi(n) for(__typeof(n.begin()) it=n.begin();it!=n.end();it++)
#define IO freopen("A.in","r",stdin),freopen("Out.out","w",stdout)
using namespace std;

///===TypeDefs=====///
typedef long long ll;
typedef unsigned long long ull;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef vector<ll> vll;
typedef vector<pii> vii;

///===Number Theory===///
//template< class T > inline T SQR(T a) { return ((a)*(a)); }
//template< class T > inline T gcd(T a,T b) {a=abs(a);b=abs(b); if(!b) return a; return gcd(b,a%b);}
//template< class T > inline T lcm(T a,T b) {a=abs(a);b=abs(b); return (a/_gcd(a,b))*b;}
//template<typename T> T POW(T b,T p) {T r=1; while(p){if(p&1)r=(r*b);b=(b*b);p>>=1;}return r;}
//template<typename T> T BigMod(T b,T p,T m) {T r=1; while(p){if(p&1)r=(r*b)%m;b=(b*b)%m;p>>=1;}return r;}
//template<typename T> T ModInverse(T n,T m) { return BigMod(n,m-2,m); }
//
/////==GeoMetry=========///
//double DEG(double x) { return (180.0*x)/(PI);}
//double RAD(double x) { return (x*(double)PI)/(180.0);}
//template<typename T> double DIS(T a,T b){ return sqrt((double)( SQR(a.X-b.X)+ SQR(a.Y-b.Y))); }
//template<typename T> T ANGLE(T a,T b){ return atan( double(a.Y-b.Y) / double(a.X-b.X));}
//template<typename T> int isLeft(T a,T b,T c) { return (c.X-a.X)*(b.Y-a.Y)-(b.X-a.X)*(c.Y-a.Y); }
//
/////===IO-Related===///
//template< class T > void prnt(T v) { fv(i,v) {if(!i)cout<<v[i];else cout<<" "<<v[i];} cout<<endl; }
//template< class T > void BIN(T n) { if(!n){nl;return;}BIN(n/2);cout<<(n%2); }
//template<typename T> T in(){ char ch; T n = 0; bool ng = false; while (1) { ch = getchar(); if (ch == '-') { ng = true; ch = getchar(); break;} if (ch>='0' && ch<='9') break; } while (1) { n = n*10 + (ch - '0'); ch = getchar(); if (ch<'0' || ch>'9') break; } return (ng?-n:n); }

///====Some-Stuff===///
// atoi( str.c_str() ); // char string to int
/// sprintf(str,"%d",num);// num to char string
///int month[]={-1,31,28,31,30,31,30,31,31,30,31,30,31}; //Not Leap Year
///int dx[]= {1,0,-1,0};int dy[]= {0,1,0,-1}; //4 Direction
///int dx[]={1,1,0,-1,-1,-1,0,1};int dy[]={0,1,1,1,0,-1,-1,-1};//8 Direction
///int dx[]={2,1,-1,-2,-2,-1,1,2};int dy[]={1,2,2,1,-1,-2,-2,-1};//Knight Direction

/**************************************************************************************
* ///////////////////////////////////////////////////////////////////////////////////*
*************************************************************************************/

///==========CONSTANTS==============///
/// Digit 0123456789*#@%&^$"- ///
#define MX 5005
#define inf 2000000000
#define MD 1000000007LL
#define eps 1e-9
///================================///

ll Lim=1000000000000000LL;
ll UL=1000000000000010LL;
ll pr[]= {2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59};
ll dp[MX+2][18];

ll go(int p,ll nd) {
if( nd ==1LL ) return 1LL;
if( p==16 ) return UL;
ll &ret=dp[nd][p];
if(ret!=-1) return ret;
ret=UL;
ll nm=1LL;
for(int i=1; i<=63; i++) {
if( nm>(UL/pr[p]) )break;
nm*=pr[p];
if( nd%(i+1)==0 ) {
ll tmp=go( p+1,nd/(i+1) );
if( nm< UL/tmp ) ret=min(ret, nm*tmp);
}
}
return ret;
}

int main() {
int tc,cs=1,i,j,k,n;
while(S(n)==1 && n) {
SET(dp);
ll ans=go(0,(ll)n);
printf("Case %d: ",cs++);
if(ans>Lim) printf("Impossible\n");
else printf("%lld\n",ans);
}
return 0;
}

Comments

Popular posts from this blog

HackerEarth: City and Campers 2 (DSU-UnionFind)

Two Pointers Technique & Binary Search For Beginners

Problem : Codeforces Round #406 (Div. 1) B [ Legacy ]( Dijakstra, Segment tree)